#!/bin/sh##方法一 判断输出字符数统计为0is_empty_dir(){     return `ls -A $1|wc -w`}##方法二 判断输出string为空#is_empty_dir(){ #   return $[ -z `ls -A $1` ]#}if is_empty_dir $1then    echo " $1 is empty"else    echo " $1 is not empty"    fi

注：参考连接：http://blog.csdn.net/10km/article/details/50427281